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update: The following have been found in Neutron Halo - Recent Experimental Progress at RIBF, Vol. 8, NO. 5 of the AAPPS Bulletin

The AAPPS Bulletin explains how the momentum distribution of 20C + 2n breakup is additional evidence of a 2 neutron halo (along with the small 2 neutron separation energy of only 0.14 MeV) but I can not follow the argument.


Halo nuclei are generally very light nuclei with a significant neutron excess. These isotopes usually decay in seconds down to milliseconds, and so are often observed as individual ions in motion. Most of the data are scattering and reaction cross-sections calculated from radioactive beam on target experiments. These isotopes are at the extreme limits of particle stability near the "neutron drip line" and the binding energy of the last one or two neutrons is usually very small compared to most nucleons.

According to the Phys.org article Experiments reveal a neutron halo around neutron-rich magnesium nuclei:

Neutron halos are a dilute cloud of neutrons that surround the more tightly packed neutrons and protons found at the center of a nucleus.

The article also says:

The researchers used RIKEN's Radioactive Isotope Beam Factory to produce nuclei of magnesium-37, consisting of 25 neutrons and 12 protons. To examine its properties, the researchers observed what happened when these nuclei were bombarded against a lead target. "We found that the magnesium-37 nuclei broke up easily into a magnesium-36 core and a single neutron," says Kobayashi. "Thus, we concluded that magnesium-37 has a neutron halo." (emphasis added)

Lead target nuclei are highly charged and this breakup may be caused by coulomb excitation sufficient to liberate the weakly bound neutron. Having a large reaction cross-section alone doesn't necessarily mean by itself that the magnesium-37 nuclei have a large physical cross-section or a large "halo". I understand that it might suggest the neutron may have a slightly larger wave function than other nucleons, but with a short-range nuclear potential, that should not be very much.

Have these halo's ever been demonstrated in non-nuclear reaction experiments, possibly with atoms at rest? Is there something more than "they break easily"?

below: from Phys.org.

enter image description here

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    $\begingroup$ What would you consider a direct measurement to be? Scattering cross sections are the norm... $\endgroup$
    – Jon Custer
    Commented Oct 27, 2017 at 17:36
  • $\begingroup$ How do you propose to do a in situ measurement in microseconds? And note that even a 'direct' measurement of a nucleon momentum distribution is a generally destructive. $\endgroup$ Commented Oct 27, 2017 at 19:26
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    $\begingroup$ @dmckee If I could imagine a way, I would have included it as part of the question. Since I can not, I've asked if anyone else has. For proton distribution, especially of heavier nuclei, there is (for example) the interaction with inner-(atomic) shell electrons using spectroscopy on nuclei stopped in a gas target. But for neutrons, I can't think of anything off the top of my head, thus my question. $\endgroup$
    – uhoh
    Commented Oct 28, 2017 at 0:17
  • $\begingroup$ @JonCuster scattering cross-section is really a transition probability that is combined with other parameters (e.g. target thickness, density) and while it happens to have units of area, it is not really interpreted as an actual measure of the cross-sectional area of a nucleus. However, the choice of the term "neutron halo" and the imagery give a more physical interpretation of a neutron far from the other nucleons. I'm asking if there are any other measurements beyond scattering cross-section that are also sensitive to the physical extent of the neutron's wave function. $\endgroup$
    – uhoh
    Commented Oct 28, 2017 at 2:04
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    $\begingroup$ True, a cross section is not a measurement of cross sectional area of a nucleus. However, the cross section does not include target thickness and density. The increase in cross section over the Rutherford cross section indicates indeed that something is different. Particularly if the result of the interaction is a neutron and the rest of the nucleus. Scattering cross sections are the very core of nuclear physics. $\endgroup$
    – Jon Custer
    Commented Oct 28, 2017 at 3:30

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The PREX and CREX experiments at Jefferson Lab are efforts to measure separately the neutron and proton charge radii in lead and calcium. The proton (charge) radius comes from the total scattering cross section. Since the neutron's weak charge is much larger than the proton's, and the weak interaction is parity-violating while the electromagnetic interaction isn't, it's possible to extract the neutron radius from the parity-violating part of the scattering cross section. This technique has given about 0.33 fm neutron skin thickness in lead-208. Note that the volume of the lead-208 neutron skin is larger than the entire volume of a lithium-11 halo nucleus; it's a thin skin, but on a big surface.

The halo nucleus discovery paper (1985) reported somewhat more distance, $0.8\pm0.2 \rm\,fm$, for the difference in matter radius between lithium-11 and its cousins lithium-6 through lithium-10. That paper uses a simple model where the interaction cross section is essentially the physical cross-sectional area of the nucleus (which doesn't sound all that terrible for a contact interaction). That early paper uses some more sophisticated models to try to extract both charge and neutron radii for its beams, and suggests that the charge radius and neutron radius for that specific isotope are only different by about 0.3 fm, but whether that difference is significant or not depends on how you read their error bars.

A few papers (lithium-11 in 2005, beryllium-11 in 2008 and -12 in 2012) extract the size of the charged part of halo nuclei by looking at shifts in the electronic spectrum due to interactions between the electron cloud and the finite-sized nucleus. Those results suggest that the charged part of the halo nuclei are a little bigger than their non-halo neighbors, but not nearly enough to explain their larger interaction cross sections.

Unfortunately it's going to be hard to do better than that approach: a measurement of the effective nuclear size from the scattering cross section, and a measurement of the charge radius from the electronic spectrum, and modeling to connect the two. To first order, the neutrons don't interact with the electrons electromagnetically, and the parity-violation trick would require you to produce a chemically significant number of the rare isotopes.

Also note that the magnesium paper you refer to (not the press release on the phys.org content farm) is substantially more complicated than "they break easily." While the paper does report neutron separation energies and neutron emission cross sections, most of the text is devoted to arguing that the final neutron is in a so-called $p$-wave orbital --- like the halo neutrons in lighter nuclei. Low orbital angular momentum is apparently set out as a condition for a "halo" nucleon in this review, which I have not read.

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  • $\begingroup$ This is a really interesting experiment! While 9Be does have a fairly weakly bound neutron, I'm not sure it has this annomalously large breakup cross-section as discussed in the quesiton, and it doesn't appear in this list of "halo nuclei" en.wikipedia.org/wiki/Halo_nucleus For isotopes near the neutron drip line, half-lives are milliseconds, so this type of experiment may be difficult to do with sufficient precision using radioactive beams. $\endgroup$
    – uhoh
    Commented Nov 15, 2017 at 14:54
  • $\begingroup$ Yes, parity-violation experiments with small asymmetries require stable targets. A better description of the effect that the P/CREX folks are after is a "neutron skin"; the dynamics of a proper "halo" are a little more complicated, even if the basic idea is the same. $\endgroup$
    – rob
    Commented Nov 15, 2017 at 15:07
  • $\begingroup$ Neutron skin is a small difference in proton and neutron radii, maybe something like 0.1 fermi roughly, a halo is supposedly "way out there" much farther and much more lonely. The problem is that as far as I know, the only thing they've got going for it is a large break-up cross-section which might simply be explained by extremely low single-neutron binding energy alone, and not really need this spatial halo. See for example the experimental cross-section for 9Be and 11Be in figure 3 in arxiv.org/abs/0809.2607 $\endgroup$
    – uhoh
    Commented Nov 15, 2017 at 15:18
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    $\begingroup$ It took me an embarrassingly long time to realize that, when you're dealing with nuclei, you can basically never escape from "extensive modeling." The review article is very illuminating, but won't include developments after 2004. I'm not yet confident enough to commit to a simple answer to your final question. $\endgroup$
    – rob
    Commented Nov 16, 2017 at 3:00
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    $\begingroup$ @uhoh Well, at first order the neutron and muon don't interact: the muon ignores the strong interaction and the neutron ignores the muon's electric charge. There's a small dipole-dipole magnetic interaction, and a much smaller neutral-current weak interaction (as with electrons). The neutron basically only participates in short-range interactions, where the strong force wins; doing non-strong neutron interaction experiments is hard. $\endgroup$
    – rob
    Commented Aug 6, 2020 at 5:12

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