What are the types of complex resistor networks where the series and the parallel law doesn't apply?There are some instances where we simply apply Wye delta conversion because that is the only way a circuit can be simplified.How to detect these kinds of networks?
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1$\begingroup$ Why do you think that there is any kind of resistor network that obeys a different law from "normal" resistor networks? $\endgroup$– Solomon SlowCommented Aug 30, 2017 at 14:27
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$\begingroup$ i don't know@jameslarge $\endgroup$– user167288Commented Aug 30, 2017 at 14:35
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$\begingroup$ one type of network is bridge network $\endgroup$– user167288Commented Aug 30, 2017 at 14:37
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$\begingroup$ It's wrong to say that laws for parallel and series combination do "not hold" for such circuits (like bridge circuits, Dely-Wye, etc.). Those laws are just not enough to solve them. $\endgroup$– CurdCommented Aug 30, 2017 at 15:42
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$\begingroup$ Possible duplicates by OP: physics.stackexchange.com/q/354515/2451 Related: physics.stackexchange.com/q/110498/2451 and links therein. $\endgroup$– Qmechanic ♦Commented Aug 30, 2017 at 17:08
2 Answers
You can use you basic equivalent resistor formulas ($R_S=R_1+R_2+R_3\dots$ or $\frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\dots$) to replace two or more resistors in a that are all in series or all in parallel. A trick I find helps identifying this case is trying to draw a circle (well actually any closed curve) around the resistors in question. If you can draw your circle so that there are just two wires crossing the circle (think of it as one wire going in and one coming out) you should be able to replace the resistors inside with a single equivalent resistor.
Where you would use the delta or Y conversion is if you are trying to simplify part of a network that you've circled that has three wires crossing the circle. Clearly this can not be replaced by a single resistor but if three resistors in the circle are arranged as a delta or Y you can convert to the other configuration using the applicable formulas.
I hope the examples in the diagrams below help. Notice in the classic bridge circuit (third diagram) there is no way to circle two or more resistors and only have two wires crossing the circle (short of circling the whole network or course).
Laws for parallel/series resistances don't hold when resistances aren't linear (i.e. V-I-graph isn't a line through the origin).
Altough it is question able if such components should be called resistors.
EDIT:
An example to make things clear:
Suppose you have two incandescent light bulbs and
you are measuring 100mA at 100V across each, i.e. a (well defined!) resistance of 1kΩ
for each bulb.
Now if connected in series and with 100V across you would not measure a current of 50mA
but considerable more.
Therefore the "law of series combination" (e.g. "current halves if two identical resistances connected in series") does not hold for light bulbs.
It is not the case that resistance (=quotient of voltage and current) of light bulbs is not well defined, it is just not independent of voltage (or current).
The reason is that V-I relationship in light bulbs is not linear (it goes through the origin but it is not a line; it would also not work out if it was a line, but
not going through the origin (e.g. a Thevenin voltage source)).
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$\begingroup$ Would the downvoter be so kind and explain what he considers wrong with this answer? $\endgroup$– CurdCommented Aug 30, 2017 at 15:50
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$\begingroup$ I don't agree that the first sentence is true and even it it were I don't think it answers the question that was asked. The OP is asking about a resistor network. I think you missing the point getting into components without a well defined resistance. $\endgroup$– M. EnnsCommented Aug 30, 2017 at 16:09
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$\begingroup$ @M. Enns: thanks for your comment. I will extend my answer to explain. Hope it makes things clear for you. BTW: are you sure you don't mix not "well defined" with non-constant (not voltage/current independent)? $\endgroup$– CurdCommented Aug 30, 2017 at 17:59