In general relativity, we can write the geodesic equation as a contraction $v^\alpha \nabla _\alpha v^\mu = f(\lambda)v^\mu$ along a path defined by coordinates $x^\mu(\lambda)$, and where $v^\mu = \frac{dx^\mu}{dt}$.
I understand how we can interpret the covariant derivative as the invariant version of partial derivative. But what I don't understand is the contraction with the velocity vector.
Nice thing about this formula is that if we think of it as sort of giving the "rate of change" along the curve. Then if we take lambda as proportional to the proper time measured by the particle from its starting point, we get $f(\lambda) = 0$ which is nice since the tangent velocity vector is "not changing" in a geodesic. This allows us to interpret the geodesic as sort of a straight path.
How can we interpret $v^\alpha \nabla _\alpha$ analogous to differentiation?