0
$\begingroup$

What arrangement will a mixture of low density gas and high density gas take inside a balloon (in a vacuum chamber) in zero gravity? FYI: water boil then freeze's in a vacuum.

which one will stick to the inside surface of the balloon and which one will be in the center?

Improve this question
$\endgroup$
2
  • $\begingroup$ In answer to your first question: I don't know why you'd ignore gravity? In answer to your fourth and final question; no. The predominating reason being that, quite intuitively, if you're reaching such temperatures I think you're probably popping the balloon before you split atoms. $\endgroup$
    – Matt
    Commented Feb 22, 2016 at 12:37
  • $\begingroup$ you ignore gravity to form sphere, for example tow liquids with different density will form layers because of gravity. $\endgroup$
    – Hammar
    Commented Feb 22, 2016 at 13:02

1 Answer 1

Reset to default
2
$\begingroup$

Assuming we can neglect intermolecular bonding (which is very small for most gases) and no chemical interreactions, then in the absence of gravity, the gases will diffuse into each other forming an even mixture (increasing entropy).

Improve this answer
$\endgroup$
1
  • $\begingroup$ what if we separated the two gases with balloons by punting the high dense gas balloon inside the low dense gas balloon. will they diffuse into each other? $\endgroup$
    – Hammar
    Commented Feb 22, 2016 at 17:13

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.