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My physics teacher says that centripetal force is caused by gravity. I'm not entirely sure how this works? How can force cause another in space (ie where there's nothing).

My astronomy teacher says that gravity is (note: not like) a 3D blanket and when you put mass on it, the mass causes a dip/dent in the blanket and so if you put another object with less mass it will roll down the dip onto the bigger mass. Is this true and is this what causes the centripetal force.

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Simple answer: gravity is a centripetal force, and can be envisaged clearly as such in Newtonian mechanics.

Centripetal just means a force that is "radially inwards" ("directed towards the centre"). The electric force between two objects of opposite charges, for example, is also clearly centripetal. (It's slightly harder to define "centripetal" for the magnetic force.)

Your astronomy teacher is referring to Einstein's theory of general relativity. His description is loosely an overview of the topology (fabric) of space-time and how it interacts with matter/energy - the manifold is however 4-dimensional, not 3D.

In fact, test particles (particles which do not really disturb the gravitational field) in general relativity follow a geodesic. This is effectively a generalisation of a straight line (shortest route) of normal Euclidian space to the curved space of GR, and may be seen as the source of centripetal force in Newtonian physics.

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  • $\begingroup$ So centripetal force is a type of force, basically like a cat is a type of animal? 4D being time? Dare I ask how gravity affects time? Thanks for the explanation and for giving links :) $\endgroup$
    – Jonathan.
    Commented Nov 7, 2010 at 19:07
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    $\begingroup$ @Jonathan: Kind of - it's just a way of classifying a force. More like saying a cat is a "tailed creature". The 4th dimension is indeed time. Basically, a strong gravitational field actually slows down time. (If you approach very near a Black hole, time becomes very slow indeed, and at the singularity itself, it may well stop, though we don't have a good idea what exactly happens.) $\endgroup$
    – Noldorin
    Commented Nov 7, 2010 at 19:51
  • $\begingroup$ You can't separate time from space so thinking about a 4th time dimension doesn't make sense, it's just a 4th spatial dimension. Think 2d surface of planet in 3d space, but 3d surface of universe on 4d multiverse space. "Space is to place as eternity is to time." $\endgroup$
    – Dagelf
    Commented Mar 26, 2016 at 8:00
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A centripetal force is a force directed towards the centre. It's just a characterisation of an existing force. "Centripetal" means "towards the centre" in Greek.

So, in the solar system, the sun exerts a gravitational force towards itself, and it is a centripetal force.

Regarding your other question: how does gravity work? According to general relativity, energetic or massive objects distort space, so that other objects passing through the distorted space do not go straight, but bend their trajectory. From their point of view, they experience a force (gravity), and consequentially an acceleration which changes their trajectory. So according to general relativity the medium through which gravity acts is actually the distortion of space. This is what your astronomy teacher called "a 3D blanket".

Instead, according to Quantum Field Theory, forces are mediated by appropriate particles actually moving through space. Gravity would be carried by particles known as gravitons.

In both these theories, there is no action-at-a-distance, so body don't exert forces on one another instantaneously, but there's always something "in the middle" that carries or represents the force.

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    $\begingroup$ This agrees mainly with my answer... However, I would say mass/energy "disturbs" rather than "distorts" space-time. Distorts makes me think of crazy things like wormholes, but maybe that's just me. :) Also, objects don't really travel through space-time in a curved trajectory; it's "straight" in that it follows a geodesic for the given manifold. $\endgroup$
    – Noldorin
    Commented Nov 7, 2010 at 17:32
  • $\begingroup$ Interesting... for me, something like a wormhole is too extreme to be characterized as a "distortion." In any case, I definitely prefer either "disturb" or "distort" to the seemingly popular choice of "curve." $\endgroup$
    – David Z
    Commented Nov 7, 2010 at 17:58
  • $\begingroup$ Yeah, that's probably a fair view too. I guess I envisage "distort" as somewhere in between in actual fact. The space-time manifold behave well (deforms smoothly) in almost all cases which is maybe why I don't like the word. $\endgroup$
    – Noldorin
    Commented Nov 7, 2010 at 19:05
  • $\begingroup$ Seeing as gravity is a particle does that mean that should the sun spontaneously dissappear we wouldn't notice gravity/orbit wise until at least 8 minutes(time light takes from sun to earth) $\endgroup$
    – Jonathan.
    Commented Nov 8, 2010 at 0:19
  • $\begingroup$ @Jonathan you would have exactly the same delay with both theories - both the gravitons and the space distortions travel at the speed of light. $\endgroup$
    – Sklivvz
    Commented Nov 8, 2010 at 8:00
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I think a key element that this student is missing is actually a very common misconception about centripetal force. We hear of various types of forces, like normal forces, frictional forces, and gravitational forces, and then we tack on "centripetal force" as if it was another type of force like that. But it's not-- those other forces are real forces with their own force laws and their own behaviors. Centripetal force is not so much a name for a force at is a name for the mass times acceleration of an object moving in a circle. So, centripetal force is not a kind of force, it is a net force that other forces have to add up to-- if and only if you already know the acceleration is that of an object moving in a circle. So for an orbiting body with only gravity on it, gravity must be the centripetal force, but if a body is orbiting with both gravity on it, and a stretched rubber band going around as well, then the force of gravity plus the force of the rubber band will be the centripetal force. In neither case is the centripetal force a type of force of its own. (Oops, just noticed the date on the question, perhaps this will be of help to someone else.)

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cetripital force only exists when you have prescribed motion (due to constraints). Think of a roller coaster car riding on a rail. To keep the car on the rail and tangetial to its direction a force and moment need to be applied to the car. When the path is circular we call the cetripetal force. In fact, with any path, instanteously it is said to be following a circle and therefore there is always an instanteneous centripetal force (unless in free fall).

Planets and things in orbit do not have a prescribed motion, but are following the free fall path whichever way they need to go. Gauss called this the principle of least action.

I hope this helps.

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Gravity is a force.

Gravity is directed towards the center of the orbit i.e. the sun.

That makes gravity the centripetal force.

Imagine a ball attached to a string and you are holding the other end of the string and moving your hand in such a way that the ball is in circular motion. Then tension in the string is centripetal force.

Now, ball = earth

you = sun

tension in the string = gravity

Hope it helps. I have no idea about general relativity.

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The difference between gravity and the centripetal force is that if the star and a planet which orbits the star are lets say:charged then gravity wont any longer be the centripetal force.

The centripetal force is not a seperate force , it is the sum of all the forces who point at the center of the rotation axis of a object rotating around the same axis

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Gravity is a fictitious force and rather equals a centrifugal force in nature due to the theory of General Relativity.

The centripetal force in everyday life embodies the proper acceleration. I say that the opposite counterpart of gravity would be the pressure force between particles, which manifests the surface (proper) acceleration of gravitating bodies.

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  • $\begingroup$ Would it be too much to ask the downvoters to tell me what logic is wrong with this answer? $\endgroup$
    – Eusa
    Commented Sep 15, 2023 at 17:51

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