1
$\begingroup$

I have recently tried to understand the differences between tensors and tensor fields. Am I correct in the statement that a tensor is defined as a linear multilinear map on a set of vector spaces and/or dual vector spaces to a field $\mathbb{R}$ or $\mathbb{C}$ (as is written in wikipedia). On the other hand a tensor field is defined as a linear multilinear map on a set of tangent vector spaces and/or dual tangent vector spaces to a field $\mathbb{R}$ or $\mathbb{C}$ (as is written in wikipedia).

If this is correct does that mean that a tensor gives as an output a global property of the vector space we put in and sharing all symmetries of the vector space? And on the other hand the tensor field tells us a local property (such as curvature at point x) of the manifold?

$\endgroup$
1
  • 2
    $\begingroup$ It's the same as the difference between a vector and a vector field. $\endgroup$
    – Javier
    Commented Sep 23, 2021 at 12:36

1 Answer 1

3
$\begingroup$

A $(p,q)$ tensor field $T$ on a smooth manifold $M$ is defined as a multilinear map: $$T : \underbrace{\Omega(M)\times\dots\times\Omega(M)}_{p\ times} \times\underbrace{\mathfrak{X}(M)\times\dots\times\mathfrak{X}(M)}_{q\ times} \to C^{\infty}(M)$$ where $\Omega(M)$ is the set of all covector fields on $M$ and $\mathfrak{X}(M)$ is the set of all vector fields on $M$.

Unpacking the above, $T$ sends $p$ covector fields $H_1,\ldots,H_p$ and $q$ vector fields $X_1,\ldots,X_q$ to some $C^{\infty}$ function $f$ on $M$. i.e., $T(H_1,\ldots,H_p,X_1,\ldots,X_q)$ is a $C^{\infty}$ function on $M$. Notationally, its effect for a point $x\in M$ is $$T_x(H_1(x),\ldots,H_p(x),X_1(x),\ldots,X_q(x))=f(x)$$ where $H_i(x)$ and $X_i(x)$ are respectively covectors and vectors in cotangent and tangent spaces at $x$. $T_x$ is defined locally at $x$ as: $$T_x:\underbrace{T^*_xM\times\dots\times T^*_xM}_{p\ times} \times\underbrace{T_xM\times\dots\times T_xM}_{q\ times} \to F$$

Thus you can see how the tensor field $T$ selects for each point $x$ a locally defined tensor acting on cotangent and tangent spaces at $x$.

To address what you wrote in the question: "a tensor is defined as a linear multilinear map on a set of vector spaces and/or dual vector spaces to a field..." - you hopefully see why this isn't accurate. Similarly, "tensor field is defined as a linear multilinear map on a set of tangent vector spaces and/or dual tangent vector spaces to a field" isn't accurate either.

$\endgroup$
5
  • $\begingroup$ Ok Thanks. So physically one might say a tensor field at point $x$ is a locally defined tensor, which in your notation is $T_x$ acting on (co-)tangent vector spaces of the point $x$ with respect to the manifold. $\endgroup$ Commented Sep 23, 2021 at 11:31
  • 1
    $\begingroup$ @krabbypatty: That's correct. However, personally I wouldn't call it a "physical" description. More of an intuitive mathematical one. $\endgroup$
    – Shirish
    Commented Sep 23, 2021 at 11:37
  • $\begingroup$ Your definition of tensor field is missing a specification of what kind of map $T$ is. Your description of $\Omega(M)$ as a set, suggests we are in the category of sets, which clearly is not enough. $\endgroup$
    – TimRias
    Commented Sep 23, 2021 at 15:36
  • $\begingroup$ @mmeent: Thanks for pointing it out! By "kind of map", I'm taking it to mean that I've failed to mention that $T$ is multilinear (maybe you meant something else by that?). As for $\Omega(M)$, I remember first learning it as a "collection of all covector fields on a smooth manifold". If I've missed a subtlety in description, could you let me know and I'll update my answer asap $\endgroup$
    – Shirish
    Commented Sep 23, 2021 at 15:48
  • $\begingroup$ Is multilinear enough here? Doesn't it need to be a morphism of $C^\infty(M)$-modules? $\endgroup$
    – TimRias
    Commented Sep 23, 2021 at 15:57

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.