Timeline for Twin paradox with two intertial frames in general relativity
Current License: CC BY-SA 3.0
9 events
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| Feb 5, 2014 at 21:51 | comment | added | Valter Moretti | <<both observers are in an inertial frame. They therefore see all clocks that follow some other path tick slower (right?)>> Actually NOT, the point is just this one: It is true in special relativity but in general is false in general relativity. | |
| Feb 5, 2014 at 18:35 | comment | added | user40000 | I understand that it is a paradox, not an inconsistency. :) My mental "problem" is with the fact that both observers are in an inertial frame. They therefore see all clocks that follow some other path tick slower (right?). So, if Alice keeps on observing Bob, she should always see his clock progress slower than her own, so when they meet again Bob's clock has fewer ticks. At the same time, when Bob keeps observing Alice, he sees her clock tick slower, with the opposite conclusion. So there must be something in the gravitational field that allows another clock to tick faster. What is that? | |
| Feb 5, 2014 at 18:00 | comment | added | Valter Moretti | I do not think that a nontrivial topology of the spatial section of spacetime is necessary to get focal points for timelike geodesics: think of a pair of rockets orbiting (just gravitation so in inertial motion) around the sun, one clockwise and the other anticlockwise... | |
| Feb 5, 2014 at 17:46 | history | edited | Valter Moretti | CC BY-SA 3.0 |
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| Feb 5, 2014 at 17:39 | history | edited | Valter Moretti | CC BY-SA 3.0 |
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| Feb 5, 2014 at 17:33 | history | edited | Valter Moretti | CC BY-SA 3.0 |
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| Feb 5, 2014 at 17:20 | comment | added | Valter Moretti | Yes I agree. Indeed I was just thinking of a 2D cylinder obtained from 2D Minkowsi spacetime where it happens exactly what you remarked. | |
| Feb 5, 2014 at 17:17 | comment | added | Zo the Relativist | Quibble: In a cylindrical universe, the gluing condition imposes a unique global reference frame in which the size of the universe is maximal. There is only perfect symmetry in the case where both observers have equal and opposite relative velocities to this global reference frame. | |
| Feb 5, 2014 at 17:11 | history | answered | Valter Moretti | CC BY-SA 3.0 |