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Jan 7, 2014 at 0:55 comment added Selene Routley Hint: The magnetic force on a charged particle is $q\vec{v}\wedge\vec{B}$, and is therefore always orthogonal to both the magnetic induction $\vec{B}$ and, most importantly, the particle's velocity. Ask yourself how much work is done by such a force. If you've not met this formula before, then you simply take as experimental fact that the force is orthogonal to the particle's velocity, and constant. This may remind you of circular motion.
Jan 6, 2014 at 17:24 review Close votes
Jan 7, 2014 at 11:55
Jan 6, 2014 at 16:10 vote accept user36867
Jan 6, 2014 at 16:09 review First posts
Jan 6, 2014 at 17:07
Jan 6, 2014 at 16:09 answer added Eric Angle timeline score: 2
Jan 6, 2014 at 15:53 history asked user36867 CC BY-SA 3.0