Timeline for Conservation of Mathematical Constraints when deriving Energy and Momentum from $F=ma$
Current License: CC BY-SA 3.0
17 events
| when toggle format | what | by | license | comment | |
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| Jan 17, 2019 at 0:19 | review | Suggested edits | |||
| Jan 17, 2019 at 6:32 | |||||
| Sep 23, 2014 at 19:15 | answer | added | Void | timeline score: 2 | |
| Sep 23, 2014 at 2:22 | answer | added | user1476176 | timeline score: 2 | |
| Aug 27, 2014 at 19:43 | answer | added | user121330 | timeline score: 3 | |
| Jul 14, 2014 at 13:33 | answer | added | steveOw | timeline score: 2 | |
| Apr 18, 2014 at 7:57 | history | edited | Hunter | CC BY-SA 3.0 |
edited title
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| Dec 18, 2013 at 23:10 | history | edited | user1476176 |
Changed tags
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| Dec 18, 2013 at 12:14 | history | edited | Qmechanic♦ |
math phys tag does not apply
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| Dec 18, 2013 at 10:10 | history | edited | user1476176 | CC BY-SA 3.0 |
Added new ideas, fixed two old typos
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| Dec 16, 2013 at 8:27 | comment | added | David Z | Yeah, that was my thought as well. After all, at least in classical mechanics, the whole rotational dynamics formalism (angular momentum, torque, etc.) is a way of eliminating degrees of freedom with trivial behavior from certain kinds of systems, namely those that exhibit pure rotational motion. | |
| Dec 16, 2013 at 8:13 | comment | added | user1476176 | That would be a very elegant resolution! I think it would lead to 'double-counting' constraints though. Suppose my particle accelerates in a circle... is that because the force is tangent to the circle at each point, or because there's a torque? I think the answer is 'either,' because the conditions are redundant. | |
| Dec 16, 2013 at 6:26 | answer | added | BMS | timeline score: 1 | |
| Dec 16, 2013 at 4:33 | history | tweeted | twitter.com/#!/StackPhysics/status/412440209180348418 | ||
| Dec 16, 2013 at 3:47 | comment | added | David Z | Good question. I think the gist is that the missing constraints in 3D turn into conservation of angular momentum, but others here are certainly better qualified than I am to show that (if I'm not wrong) so I'll leave it to someone else to write an answer. | |
| Dec 16, 2013 at 3:37 | review | First posts | |||
| Dec 16, 2013 at 3:40 | |||||
| Dec 16, 2013 at 3:35 | history | edited | David Z |
edited tags
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| Dec 16, 2013 at 3:19 | history | asked | user1476176 | CC BY-SA 3.0 |