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Qmechanic
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Calculating the solar power hitting earthEarth

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aaazalea
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Calculating the solar power hitting earth

I'm trying to calculate the amount of power from the sun hitting the earth, but I am getting a number which is off by a factor of ~4.

I calculate the "area" of the earth, as seen from the sun, and then divide that by the surface area of a sphere of radius 1 AU, to get the portion of the sun's rays we absorb, and then I multiply that by the solar luminosity.

Mathematica gives me this:

\text{UnitConvert}\left[\frac{\pi  \text{Quantity}[\text{AstronomicalData}[\text{Earth},\text{Diameter}],\text{m}]^2}{4 \pi  \text{Quantity}[1,\text{astronomocal units}]^2} \text{L}_{\odot },\text{W}\right]

But when I put it into Wolfram|alpha, I get this result:

4 x mean solar power intercepted by earth

Am I doing something wrong? where could that big an error be introduced? Is "mean power intercepted by earth" different than what I'm calculating?