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Dec 2, 2013 at 19:56 history edited Danu CC BY-SA 3.0
Made it explicitly clear why P doesnt have to be averaged.
Dec 2, 2013 at 19:54 comment added Danu @joshphysics fair enough, I'll edit it. Just for the record though, I am of course well aware of the concept of average power, I just thought it was a good idea to make it explicit and clear that it is not relevant in this case.
Dec 2, 2013 at 19:24 comment added user1949350 Now I'm confused... "P=Fv is an expression that holds between the instantaneous power, the force, and the velocity" Can you please elaborate this a bit more?
Dec 2, 2013 at 19:15 comment added joshphysics -1: "Power is an instantaneous concept: there is no question of averaging." That's misleading; average power can, in fact, be defined and is a very useful concept. Did you mean to say something like "$P=Fv$ is an expression that holds between the instantaneous power, the force, and the velocity"?
Dec 2, 2013 at 19:11 vote accept user1949350
Dec 2, 2013 at 19:01 history answered Danu CC BY-SA 3.0