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Nov 18, 2013 at 22:24 comment added Jesus @Carl Witthoft: I was not asking about why the voltage is high and the current is low in power lines. I feel that I understand that very well.
Nov 18, 2013 at 22:20 comment added Jesus @Bjorn Wesen: Let me try to be more clearer. A high voltage line means it is measured relative to the ground. If true, can I think of a high voltage line as an "equipotential?" This is tricky because it's ac, not dc, so I really do not know enough at the moment to say so. I follow when you ask to think of voltage more like pressure, but what sets up the "pressure difference" in the wires? Are you telling me it is not charge?
Nov 18, 2013 at 18:17 comment added Carl Witthoft To be fair, if you ignore the OP's commentary and just answer the question title, that may help a lot of lurkers. The answer of course is that power P= V * I but wires dislike carrying a lot of I so bumping up the V delivers more power with less physical wire :-)
Nov 18, 2013 at 17:16 history answered BjornW CC BY-SA 3.0