Timeline for Determine the maximum and minimum acceleration from the velocity field [closed]
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Dec 11 at 20:20 | history | left closed in review |
Amit Miyase John Rennie |
Original close reason(s) were not resolved | |
| Dec 11 at 18:33 | comment | added | Amit | In direct relation to what gandalf61 points out: it would be better if you cite the precise problem, including if possible the name of the source, page number, etc. | |
| Dec 11 at 18:30 | review | Reopen votes | |||
| Dec 11 at 20:20 | |||||
| Dec 11 at 18:29 | comment | added | gandalf61 | I'm not sure that the claim is true. Suppose the velocity of the fluid is everywhere parallel to the y axis. Then its speed at $(2,1,5)$ is $3$ m/s, and its acceleration is $4y \frac {dy}{dt} = 12$ m/s/s. | |
| Dec 11 at 16:33 | history | closed |
Bob D Vincent Thacker Matt Hanson |
Not suitable for this site | |
| Dec 11 at 16:08 | review | Close votes | |||
| Dec 11 at 16:33 | |||||
| Dec 11 at 13:58 | history | edited | lucas bublitz | CC BY-SA 4.0 |
deleted 9 characters in body
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| Dec 11 at 13:53 | comment | added | Ghoster | Then please edit your post to correct your incorrect description of $v$. An unclear question cannot be clarified by a comment. | |
| Dec 11 at 13:50 | comment | added | lucas bublitz | Yes. This question is from a civil service examination, so in my opinion it was designed to be answered quickly. Therefore, I don't think you need the velocity field to find the maximum and minimum possible acceleration. | |
| Dec 11 at 13:46 | history | edited | Amit |
edited tags
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| Dec 11 at 13:40 | history | edited | lucas bublitz | CC BY-SA 4.0 |
edited body
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| Dec 11 at 13:40 | comment | added | Ghoster | $v = 2x^3 + 2y^2 - 3z$ is a single number, so it isn’t the velocity field. Did you mean that it’s the speed field? | |
| S Dec 11 at 13:25 | review | First questions | |||
| Dec 11 at 14:20 | |||||
| S Dec 11 at 13:25 | history | asked | lucas bublitz | CC BY-SA 4.0 |