Timeline for How does a mirror lose mass during photon reflection?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 7 at 9:09 | comment | added | Ruffolo | I don't know if I understand this question, but for me, the geodesic path only makes sense if we are in the geometric limit of optics. Diffraction could be understood as a deviation from geodesic propagation, since it is a wave feature of light. | |
| Dec 6 at 21:00 | comment | added | HolgerFiedler | Reading the fundamental works of science is the basis for independent and creative thinking. Ruffolo how do you think about Is it possible to make a light follow a non-geodesic path? | |
| Dec 5 at 16:41 | comment | added | Ruffolo | That is impossible. Consider for simplicity that the mirror is at rest. If the observer is in the same frame of the mirror, it observes the same frequency of light before absorption, but the mirror adquire velocity after absorption, so there will be doppler shift. If the observer is moving in relation to the atom initially, it will observe a difference frequency that absorbed by the atom, and again there will be Doppler shift. | |
| Dec 5 at 15:17 | comment | added | Kim | In this problem, the frame of reference is not attached to the mirror. Since the analysis is conducted from a third-party reference frame, the Doppler effect does not occur. | |
| Dec 5 at 14:52 | history | answered | Ruffolo | CC BY-SA 4.0 |