Skip to main content
deleted 49 characters in body
Source Link
Qmechanic
  • 212.7k
  • 48
  • 589
  • 2.3k

I apply a force on an object. The object applies an equal and opposite force on me. I realize the forces are on two distinct bodies and do not cancel each other out. Accordingly, the work done by me and the work done by the object are being applied on and by different objects.

However, the work done by me on the object is $F\times{}d$ and the work done by the object on me is the same. If a body does $x$ joules of work, and has $x$ joules of work done on it, there should be no change in the total energy of the object. The work done by it and on it is equal. How can this be possible? Has the object not gained kinetic energy?

Not a duplicate of Newton's Third Law and Work Done on a BodyNewton's Third Law and Work Done on a Body. My question is about the perspective of a single box rather than of the whole system.

I apply a force on an object. The object applies an equal and opposite force on me. I realize the forces are on two distinct bodies and do not cancel each other out. Accordingly, the work done by me and the work done by the object are being applied on and by different objects.

However, the work done by me on the object is $F\times{}d$ and the work done by the object on me is the same. If a body does $x$ joules of work, and has $x$ joules of work done on it, there should be no change in the total energy of the object. The work done by it and on it is equal. How can this be possible? Has the object not gained kinetic energy?

Not a duplicate of Newton's Third Law and Work Done on a Body. My question is about the perspective of a single box rather than of the whole system.

I apply a force on an object. The object applies an equal and opposite force on me. I realize the forces are on two distinct bodies and do not cancel each other out. Accordingly, the work done by me and the work done by the object are being applied on and by different objects.

However, the work done by me on the object is $F\times{}d$ and the work done by the object on me is the same. If a body does $x$ joules of work, and has $x$ joules of work done on it, there should be no change in the total energy of the object. The work done by it and on it is equal. How can this be possible? Has the object not gained kinetic energy?

Not a duplicate of Newton's Third Law and Work Done on a Body. My question is about the perspective of a single box rather than of the whole system.

Post Reopened by gandalf61 newtonian-mechanics
Resolved close reason - though I'm not sure what connection that question had to mine.
Added to review
Source Link

I apply a force on an object. The object applies an equal and opposite force on me. TheI realize the forces are on two distinct bodies and do not cancel each other out. Accordingly, the work done by me and the work done by the object are being applied on and by different objects.

However, the work done by me on the object is $F\times{}d$ and the work done by the object onon me is the same. Therefore no netIf a body does $x$ joules of work was, and has $x$ joules of work done on the objectit, asthere should be no change in the total energy of the object. The work done by it and on it is equal. How can this be possible? Has the object not gained kinetic energy?

Not a duplicate of Newton's Third Law and Work Done on a Body. My question is about the perspective of a single box rather than of the whole system.

I apply a force on an object. The object applies an equal and opposite force on me. The work done by me on the object is $F\times{}d$ and the work done by the object on me is the same. Therefore no net work was done on the object, as the work done by it and on it is equal. How can this be possible? Has the object not gained kinetic energy?

Not a duplicate of Newton's Third Law and Work Done on a Body. My question is about the perspective of a single box rather than of the whole system.

I apply a force on an object. The object applies an equal and opposite force on me. I realize the forces are on two distinct bodies and do not cancel each other out. Accordingly, the work done by me and the work done by the object are being applied on and by different objects.

However, the work done by me on the object is $F\times{}d$ and the work done by the object on me is the same. If a body does $x$ joules of work, and has $x$ joules of work done on it, there should be no change in the total energy of the object. The work done by it and on it is equal. How can this be possible? Has the object not gained kinetic energy?

Not a duplicate of Newton's Third Law and Work Done on a Body. My question is about the perspective of a single box rather than of the whole system.

edited tags
Link
Qmechanic
  • 212.7k
  • 48
  • 589
  • 2.3k
Post Closed as "Duplicate" by naturallyInconsistent, John Rennie newtonian-mechanics
Source Link
Loading