Timeline for Understanding instantaneous rest frames in general relativity
Current License: CC BY-SA 4.0
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| Nov 13 at 6:01 | history | edited | weeab00 | CC BY-SA 4.0 |
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| Nov 13 at 0:25 | history | edited | weeab00 | CC BY-SA 4.0 |
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| Nov 13 at 0:02 | comment | added | weeab00 | Related: physics.stackexchange.com/questions/714606/… | |
| Nov 10 at 23:56 | comment | added | Miss Understands | >> In the instantaneous rest frame, dτ=0. === Okay, but how is that different from the null surface, which is the 4-cone surface on which no time passes? | |
| Nov 9 at 9:39 | history | edited | Qmechanic♦ |
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| Nov 8 at 7:36 | comment | added | naturallyInconsistent | The concept still works, but its range of validity is tiny. You cannot flatten the metric to the SR one. The best that you can do to make it almost the SR one, is to use Riemann normal coördinates. Even then, the metric is flat at the point of consideration, but continues to have the Riemann curvature term, so that only the infinitesimal neighbourhood is flattened. | |
| Nov 8 at 7:17 | history | edited | weeab00 | CC BY-SA 4.0 |
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| Nov 8 at 6:31 | history | asked | weeab00 | CC BY-SA 4.0 |