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Nov 7 at 15:38 comment added Agnius Vasiliauskas Also see Vacuum expectation value.
Nov 7 at 15:18 comment added Agnius Vasiliauskas @TobiasFünke Or you can check Planck's oscillator average energy equation : $$ \varepsilon ={\frac {h\nu }{2}}+{\frac {h\nu }{e^{h\nu /(kT)}-1}}~. $$ Term ${\frac {h\nu }{2}}$ also has same meaning like in my previous given equation. Why people speak about ZPE if no such energy level exist according to you ? As a proof of this lowest energy level possible is Casimir effect.
Nov 7 at 15:13 comment added Agnius Vasiliauskas @TobiasFünke Citation from wiki: Likewise, it can never have zero energy, meaning that the particle can never "sit still" Oh yes, there is such law, check Zero point energy, which defines expectation value of resonator energy : $$ \left\langle {\hat {H}}\right\rangle =V_{0}+{\frac {\hbar \omega }{2}} $$. So every QM resonator/oscillator must have at least ${\frac {\hbar \omega }{2}}$ of energy scaled by some natural frequency.
Nov 7 at 15:10 comment added Tobias Fünke ...and this PSE post... and probably many more.
Nov 7 at 15:02 comment added Tobias Fünke What are you talking about? Every constant shift in the Hamiltonian leaves the physics completely unchanged. There is no axiom in QM that says something about the ground state energy. See also this PSE post.
Nov 7 at 13:58 comment added Agnius Vasiliauskas @JEB This one is the most funniest way to abuse QM 😄🤣
Nov 7 at 12:56 comment added JEB ...or you can do a particle in a sunken box: $V(x) \rightarrow V(x) - h^2/(8mL^2)$ and then $E_1 = 0$. But no one does that. But you could.
Nov 7 at 9:00 history answered Agnius Vasiliauskas CC BY-SA 4.0