Timeline for Polarisation during 2 crossed polarisers
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
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Oct 29 at 19:58 | comment | added | Ruffolo | Let us continue this discussion in chat. | |
Oct 29 at 18:54 | comment | added | Assassins Hunter | One last thing how depolarized light is mixture of 2 incoherent sources in the above video if they are obtained from same source .Also please upvote my question if you liked it @Ruffolo. | |
Oct 29 at 16:17 | comment | added | Ruffolo | That's right. Please check Feynman lectures Vol I, chapter 32-4 about Independent Sources feynmanlectures.caltech.edu/I_32.html#Ch32-S1 | |
Oct 29 at 13:40 | comment | added | Assassins Hunter | Good frequency filters will still not be able to make them exactly of same frequency ? and each point source existing in one bulb itself are emiting different frequency that is why they are incoherent and they wouldnt even interefere with themselves right? Please tell if the above statements are right or wrong @Ruffolo. | |
Oct 29 at 12:25 | comment | added | Ruffolo | Of course the frequency matters, but even if you use good frequency filters, you'll not observe interference. Light bulbs emit black body radiation, which is known to be high incoherent. Each atom in the bulb behaves like a point source, and each of them have a different phase. A light from a light bulb would not even interfere with itself | |
Oct 29 at 11:08 | comment | added | Assassins Hunter | Please rectify me @Ruffolo if my above statement is wrong with proper explaination. | |
Oct 29 at 10:11 | comment | added | Assassins Hunter | The 2 bulbs are incoherent because their frequency is not exactly equal or their phase difference is time dependent, it not because of they are not in phase but rather their phase difference is time dependent and that is why they are incoherent. @Ruffolo. | |
Oct 29 at 9:21 | comment | added | Ruffolo | When we turn on two light bulbs at home, we don't observe interference between their lights. There are a mixture of both waves, but it is a incoherent mixture. It happens because they are not in phase. Now, sometimes it's said that there are no correlation between the waves. This term comes from quantum optics as I now, but you should check. | |
Oct 29 at 9:18 | comment | added | Ruffolo | A depolarized light can be thought as a mixture of waves. Usually, when we have two or more waves in phase, we have interference effect, where they will sum up it's amplitudes. When it happens, we say the waves are in a coherent mixture. Now we have a situation where waves are not in phase. In such cases, the mixture does not show interference effect. The resulting intensity is just the sum of intensities. We call it incoherent mixture | |
Oct 29 at 8:13 | comment | added | Assassins Hunter | Can you explain this line "Such incoherent mixtures does not present interference effects, since we don't have correlation between the component waves in the mixture." present in your statement in a more simpler way @Ruffolo. | |
Oct 28 at 15:17 | history | answered | Ruffolo | CC BY-SA 4.0 |