Timeline for Scaling transformation confusion [duplicate]
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Oct 28 at 16:13 | comment | added | Connor Behan | It's easy to notice which transformation of $x^2$ will give the right answer. The linked question is about why making $x_\mu$ pick up $\lambda$ and $x^\mu$ pick up $1/\lambda$ is wrong. | |
| Oct 28 at 10:03 | comment | added | Geigercounter | @ConnorBehan I understand with what's written in the linked question, but I don't understand how $x_\mu$ should transform then. Could you maybe give some details? | |
| Oct 28 at 10:01 | history | edited | Geigercounter | CC BY-SA 4.0 |
added 223 characters in body
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| Oct 27 at 23:34 | history | closed |
Connor Behan Matt Hanson Miyase |
Duplicate of Why do scalars scale? | |
| Oct 27 at 21:36 | review | Close votes | |||
| Oct 27 at 23:34 | |||||
| Oct 27 at 21:30 | comment | added | Connor Behan | It is not more subtle than the difference between an active and a passive transformation... $f$ should not be invariant. | |
| Oct 27 at 21:26 | comment | added | Geigercounter | I think this question is a bit more subtle, because I'm not really concerned with the transformation of the fields, but more so with the correlation function and the transformation of the function $f(x)$ in terms of $x^\mu$. | |
| Oct 27 at 21:13 | comment | added | Connor Behan | This question is similar to: Why do scalars scale?. If you believe it’s different, please edit the question, make it clear how it’s different and/or how the answers on that question are not helpful for your problem. | |
| Oct 27 at 17:50 | history | asked | Geigercounter | CC BY-SA 4.0 |