Timeline for When two black holes spinning in opposite directions approach one another is the Kerr metric destroyed as two regions of frame-dragged space meet?
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Oct 26 at 9:18 | vote | accept | CommunityBot | ||
| Oct 26 at 5:39 | answer | added | safesphere | timeline score: 1 | |
| Oct 24 at 17:54 | comment | added | user441992 | @Ghoster. Yes I take your point about the frames "meeting"! | |
| Oct 24 at 17:48 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited tags; edited title
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| Oct 24 at 17:45 | comment | added | Ghoster | Gravitational waves would be emitted but only for a short period of time. We measure this stuff at LIGO. I notice that you simply ignored what I told you about “the frames” “meeting”, so I don’t think further discussion will be productive. | |
| Oct 24 at 17:43 | comment | added | user441992 | @Ghoster. Where the frames meet do gravitational waves get emitted and the black hole spins slower.If waves are emitted then shcwarzschild metric won't exist since stationary black holes would not emit gravitational waves. | |
| Oct 24 at 17:41 | comment | added | Ghoster | It doesn’t make sense to say “where the frames meet”. There aren’t two distinguishable “frames”. The Schwarzschild metric would apply at $t=\infty$, assuming I’m right that it settles into a Schwarzschild metric. Calculating this would take a supercomputer. | |
| Oct 24 at 17:39 | history | edited | user441992 | CC BY-SA 4.0 |
edited title
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| Oct 24 at 17:32 | comment | added | controlgroup | @BenWyvis The Kerr metric describes one rotating black hole, not two. You can't just add spacetimes together except in the weak-field limit (which Kerr objects definitely do not satisfy). | |
| Oct 24 at 17:31 | comment | added | Ghoster | It doesn’t make sense to talk about metrics being “destroyed” or “conserved”. The overall metric simply evolves. If the spins were opposite but equal in magnitude I would expect it to evolve to a Schwarzschild metric. | |
| Oct 24 at 17:31 | comment | added | user441992 | @controlgroup. Surely this depends on how close the black holes get? I am asking how much distortion of Kerr metric would be caused? | |
| Oct 24 at 17:29 | comment | added | controlgroup | The moment you added a second black hole, the Kerr metric became completely invalid. The Einstein field equations are highly nonlinear; the sum of two solutions is not, generally, also a solution. | |
| S Oct 24 at 17:16 | review | First questions | |||
| Oct 24 at 19:24 | |||||
| S Oct 24 at 17:16 | history | asked | user441992 | CC BY-SA 4.0 |