Skip to main content
6 events
when toggle format what by license comment
Oct 21 at 19:09 comment added Reader Sir , I have also got another way of solving this problem . We can first represent the position eigenvector in terms of momentum eigenvectors which are also kinetic energy eigenvectors (|p》=|(ke∗2m)^{.5}》 ). For a particular position at a time , potential energy is fixed so kinetic energy eigenvector is total energy or simply hamiltonian eigenvector . Am I correct ?
Oct 21 at 16:03 history edited Cosmas Zachos CC BY-SA 4.0
added 131 characters in body
Oct 21 at 10:39 history edited Cosmas Zachos CC BY-SA 4.0
added 6 characters in body
Oct 21 at 2:49 vote accept Reader
Oct 20 at 21:21 history edited Cosmas Zachos CC BY-SA 4.0
added 114 characters in body
Oct 20 at 21:05 history answered Cosmas Zachos CC BY-SA 4.0