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Oct 15 at 15:03 comment added mmesser314 3blue1brown has a series of videos on physics. for an explanation of why the wavelength changes in a medium, see But why would light "slow down"? | Optics puzzles 3
Oct 15 at 13:02 comment added Root Groves Macron also its better to use η when talking about wave propagation because cε cannot contain phase shift between E and H while η does.
Oct 15 at 12:48 answer added Root Groves timeline score: 0
Oct 15 at 10:52 comment added James An electromagnetic wave leaves various traces/wakes of its passing, but a photon leaves theoretically no trace of its passing, so the photon seems to be a more confined "particle"-form of energy transfer compared to an arbitrary electromagnetic wave-based energy transfer.
Oct 15 at 10:45 history edited Qmechanic
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S Oct 15 at 10:38 history suggested Refik Mansuroglu CC BY-SA 4.0
Cleaned up Latex expressions and grammar errors/missing articles etc.
Oct 15 at 10:34 review Close votes
Oct 15 at 11:27
Oct 15 at 10:18 comment added naturallyInconsistent You need to be clearer with your questions. You really have two questions, mostly unrelated to each other, mashed into one post. For free space, there is really no problem; the classical intensity expression is easily connected to the quantum expression by changing the number of photons per unit time. As for the behaviour of electromagnetic energy inside a material, the fight between people who believe different expressions should be considered, is still ongoing, after almost a century. You should just look it up.
Oct 15 at 10:18 review Suggested edits
S Oct 15 at 10:38
Oct 15 at 10:16 comment added Ofek Gillon The energy of a single photon is $hf$, and in vacuum $f=c/\lambda$ so the formula you wrote is true in vacuum but not in different media. f doesn't change when entering a medium
Oct 15 at 10:06 history asked Macron CC BY-SA 4.0