Timeline for Four-point function in CFT, two constraints are missing
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Oct 15 at 0:46 | comment | added | Connor Behan | No, it's the same approach. There is no way to get 6 constraints because you could have equally well made the numerator $u^r v^s f(u, v)$ for any $r$ and $s$. | |
| Oct 14 at 23:17 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
added 12 characters in body; edited title; edited tags
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| Oct 14 at 22:20 | comment | added | Amateur Physicist | A similar question is asked (physics.stackexchange.com/q/512322) I guess his answer uses a different approach, as he doesn't have 6 constraints. | |
| Oct 14 at 22:19 | history | asked | Amateur Physicist | CC BY-SA 4.0 |