Skip to main content
added 105 characters in body
Source Link

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x).\tag{1}$$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x).\tag{2.121}$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.

EDIT: To clarify a little bit, I don't fully understand why the prime appears in the second equation.

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x).\tag{1}$$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x).\tag{2.121}$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x).\tag{1}$$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x).\tag{2.121}$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.

EDIT: To clarify a little bit, I don't fully understand why the prime appears in the second equation.

added 19 characters in body; edited tags
Source Link
Qmechanic
  • 212.7k
  • 48
  • 589
  • 2.3k

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x) $$$$ \phi'(x') = \phi(x).\tag{1}$$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x)$$$$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x).\tag{2.121}$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x) $$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x)$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x).\tag{1}$$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x).\tag{2.121}$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.

Source Link

Why do scalars scale?

The diffeomorphism invariance of scalars is often written as: $$ \phi'(x') = \phi(x) $$ However, while scaling transformation is a type of diffeomorphism, in many places (say Di Francesco, Matthieu and Senechal page 38), you see the following for scalar fields: $$\phi'(\lambda x)=\lambda^{-\Delta} \phi(x)$$ This is taken to define the scaling dimension $\Delta$. Aren't these two definitions incongruent unless the scaling dimension is 0? I'm guessing no, I just have trouble seeing what is supposed to be happening here.