Timeline for Proper Time in Eddington Finklestein Coordinates not calculable?
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
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Sep 18 at 16:57 | vote | accept | Agatha Harkness | ||
Sep 18 at 15:10 | history | edited | Qmechanic♦ |
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Sep 18 at 14:51 | answer | added | Dale | timeline score: 1 | |
Sep 18 at 14:48 | comment | added | controlgroup | $r<2M$ is within an event horizon, isn’t it? | |
Sep 18 at 14:45 | comment | added | Agatha Harkness | i agree about dr but $$d\upsilon$$ needs to be positive if we're looking at the future, doesn't it? | |
Sep 18 at 14:43 | comment | added | Dale | You are assuming that $dv$ and $dr$ have the same sign. Also it is $dv^2$, not $d^2v$. Same with $\theta$ and $\phi$ | |
Sep 18 at 14:31 | comment | added | Agatha Harkness | cause $$d\tau^2 = (1-\frac{2M}{r})d^2\upsilon -2d\upsilon dr -r^2 (d^2 \theta + sin^2 \theta d^2 \phi)$$ which basically only adds negative factors for r<2M | |
Sep 18 at 14:14 | comment | added | Dale | With the sign convention you are using you will have negative $ds^2$ for spacelike lines, not for timelike worldlines. Why do you think otherwise? | |
Sep 18 at 14:05 | history | edited | Agatha Harkness | CC BY-SA 4.0 |
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Sep 18 at 13:56 | history | edited | Agatha Harkness | CC BY-SA 4.0 |
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Sep 18 at 13:38 | history | asked | Agatha Harkness | CC BY-SA 4.0 |