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How exactly prove (11.50) and (11.52) from Lorentz transform ?

$ t'' = t' - \frac{\mathbf{x'}}{c^2} \gamma (\delta \mathbf{v} + (\gamma - 1) \frac{\mathbf{v}\mathbf{\delta v}}{v^2}\mathbf{v})$

$ \mathbf{x''} = \mathbf{x'} + (\gamma - 1)(\mathbf{x'} \times (\frac{\mathbf{v} \times \mathbf{\delta v}}{v^2})) - \Delta \mathbf{v} t'$

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How exactly prove (11.50) and (11.52) from Lorentz transform ?

enter image description here

How exactly prove (11.50) and (11.52) from Lorentz transform ?

$ t'' = t' - \frac{\mathbf{x'}}{c^2} \gamma (\delta \mathbf{v} + (\gamma - 1) \frac{\mathbf{v}\mathbf{\delta v}}{v^2}\mathbf{v})$

$ \mathbf{x''} = \mathbf{x'} + (\gamma - 1)(\mathbf{x'} \times (\frac{\mathbf{v} \times \mathbf{\delta v}}{v^2})) - \Delta \mathbf{v} t'$

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How exactly to prove Thomas precession from Jacson first ed

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How exactly prove (11.50) and (11.52) from Lorentz transform ?