When we know that the electric field outside a uniformly charged sphere is the field of a point charge placed atin the center of the sphere, it is sufficient to use Newton's Third Law to prove that the two spheres act on each other with the same forces as two point charges. There is no need to consider integrals, this is an exercise in logic. Indeed, the first sphere acts on the second sphere with the same force as a point charge atin the center of the first sphere. Consequently, the second sphere acts on the first sphere with the same force with which it acts on a point charge atin the center of the first sphere. But the second sphere acts on a point charge as a point charge atin its center.
Update. While I think the original version of my answer is sufficient, afterAfter the questioner's comment I decided to give a little more detaildetailed answer. We will consider the second charged sphere as a set of infinitesimal charges $e_i$ with coordinates $\vec{r}_i$. Then the force with which the first sphere acts on the second sphere is equal to $$ \vec{F}_{12} = \sum_i e_i \vec{E}_i^{(1)}, $$ where $\vec{E}_i^{(1)}$ is the electric field created by the first sphere at the point $\vec{r}_i$. In the case when the center of the first sphere is atin the coordinate center, we have $$ \vec{E}_i^{(1)} = \frac{kQ_1\vec{r}_i}{|\vec{r}_i|^3} $$ and accordingly $$ \vec{F}_{12} = Q_1\sum_i \frac{ke_i\vec{r}_i}{|\vec{r}_i|^3} = -Q_1 \vec{E}_0^{(2)}, $$ where $$ \vec{E}_0^{(2)} = -\sum_i \frac{ke_i\vec{r}_i}{|\vec{r}_i|^3} $$ is the electric field created by the second sphere atin the center of the first sphere center. In the case when the center of the second sphere center is at the point $\vec{R}$, we have $$ \vec{E}_0^{(2)} = -\frac{kQ_2\vec{R}}{|\vec{R}|^3} $$ After all we obtain $$ \vec{F}_{12} = \frac{kQ_1Q_2\vec{R}}{|\vec{R}|^3} $$