Timeline for Force, constant velocity, and 0 velocity
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Nov 1, 2013 at 4:28 | comment | added | pran | You are right. I was only talking about constant acceleration and accidentally missed the m in my equation. In reality, any higher force in any form would result in a deceleration that would lead to the body stopping after a while. | |
| Oct 26, 2013 at 21:18 | comment | added | jinawee | The applied force could be $F=-F_0-mv/t$, but this if you want constant acceleration. In general, the force could have any form. | |
| Oct 26, 2013 at 21:15 | comment | added | pran | I guess the summary is that you have to have a force that counters the existing force on the body + force that is required to change velocity from the current velocity to 0 in the desired time or Frequired = Fcurrent + v/t where v is the current velocity and t is the time in which you want to stop the body. The quicker the time, the higher the required force. | |
| Oct 26, 2013 at 21:03 | history | edited | jinawee | CC BY-SA 3.0 |
added 58 characters in body
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| Oct 26, 2013 at 20:50 | history | answered | jinawee | CC BY-SA 3.0 |