Timeline for Time-evolution operator in QFT

8 events

when toggle format	what		by	license	comment
Jun 25 at 12:10	vote	accept	Andrea
Jun 24 at 15:33	history	edited	Valter Moretti	CC BY-SA 4.0	deleted 1 character in body
Jun 24 at 15:09	history	edited	Valter Moretti	CC BY-SA 4.0	added 7 characters in body
Jun 24 at 15:05	comment	added	Valter Moretti		YES: When you integrate $T_{00}$ over the rest space $\Sigma$ in $d^3x$, the $\vec{x}$ dependence disappears and the $t$ dependence disappears as well because the integral is a constant of motion. That is true also for the $\phi^4(x)$ model, of course.
Jun 24 at 13:10	comment	added	Andrea		Asking cause a common example to get Feynman rule in the books is to use the interaction $\phi^4$ so in this case it depends on $\phi(x)$ and then on $t$ indirectly through $x$
Jun 24 at 13:04	comment	added	Andrea		About homogeneity of time, does that mean $H$ indirectly depends on the 4-vector $x$ and then on t, through the field $\phi(x)$, but in the end it's a constant of motion? In other words, does in this case the Hamiltonian can still depend indirectly on time?
Jun 24 at 12:17	history	edited	Valter Moretti	CC BY-SA 4.0	added 231 characters in body
Jun 24 at 10:11	history	answered	Valter Moretti	CC BY-SA 4.0