Timeline for Bound Charges in Polarized Material
Current License: CC BY-SA 4.0
3 events
when toggle format | what | by | license | comment | |
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Jun 13 at 19:18 | answer | added | VnabP23 | timeline score: 1 | |
Jun 13 at 18:24 | comment | added | mike stone | The prime is there because you are integrating over $d\tau'$, and ${\bf P}$ is a function of ${\bf r}'$ and not of ${\bf r}$. Consequently the derivative inside the integal is with respect to ${\bf r}'$ --- hence the prime on the $\nabla$ to indicate this. In the other contexts there is no ${\bf r}'$ so no need for a prime on the $\nabla$'s. | |
Jun 13 at 18:05 | history | asked | ReggiePlasmaQs | CC BY-SA 4.0 |