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Timeline for Bound Charges in Polarized Material

Current License: CC BY-SA 4.0

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Jun 13 at 19:18 answer added VnabP23 timeline score: 1
Jun 13 at 18:24 comment added mike stone The prime is there because you are integrating over $d\tau'$, and ${\bf P}$ is a function of ${\bf r}'$ and not of ${\bf r}$. Consequently the derivative inside the integal is with respect to ${\bf r}'$ --- hence the prime on the $\nabla$ to indicate this. In the other contexts there is no ${\bf r}'$ so no need for a prime on the $\nabla$'s.
Jun 13 at 18:05 history asked ReggiePlasmaQs CC BY-SA 4.0