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Why does the effect of a dielectric fully inserted between a parallel plate capacitor differ when the capacitor is connected to a battery source and when it is not?

When a charged capacitor is not connected to a battery, its potential difference can be defined as

$$V=\dfrac{V_\text{initial}}{K}$$

where $V_\text{initial}$ refers to the potential difference prior to the insertion of the dielectric and K is the dielectric constant.

However, when the capacitor is connected to a battery source, the potential difference remains the same, even when a dielectric is inserted inside the capacitors. What is the reason for this?

Why does the effect of a dielectric fully inserted between a parallel plate capacitor differ when the capacitor is connected to a battery source and when it is not?

When a charged capacitor is not connected to a battery, its potential difference can be defined as $$V=\frac{V_\text{initial}}{K}$$ where $V_\text{initial}$ refers to the potential difference prior to the insertion of the dielectric and $K$ is the dielectric constant.

However, when the capacitor is connected to a battery source, the potential difference remains the same, even when a dielectric is inserted inside the capacitors. What is the reason for this?

Why does the effect of a dielectric fully inserted between a parallel plate capacitor differ when the capacitor is connected to a battery source and when it is not?

When a charged capacitor is not connected to a battery, its potential difference can be defined as

V=V(initial) / K

where V(initial) refers to the potential difference prior to the insertion of the dielectric and K is the dielectric constant.

However, when the capacitor is connected to a battery source, the potential difference remains the same, even when a dielectric is inserted inside the capacitors. What is the reason for this?

Why does the effect of a dielectric fully inserted between a parallel plate capacitor differ when the capacitor is connected to a battery source and when it is not?

When a charged capacitor is not connected to a battery, its potential difference can be defined as

$$V=\dfrac{V_\text{initial}}{K}$$

where $V_\text{initial}$ refers to the potential difference prior to the insertion of the dielectric and K is the dielectric constant.

However, when the capacitor is connected to a battery source, the potential difference remains the same, even when a dielectric is inserted inside the capacitors. What is the reason for this?