Timeline for Why the kinetic term of the Hamiltonian has to be positive definite for well-posed time evolution?
Current License: CC BY-SA 4.0
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| Jun 3 at 4:36 | comment | added | codebpr | Thanks for the reply. The first eigenvalue $\omega_0^2$ is negative(-1.40), but that is bound to happen since the system is unstable and shows chaos. Why does the author state that "kinetic term of Hamiltonian" explicitly? Does it carry any greater significance? | |
| Jun 2 at 15:00 | comment | added | Ali | The verification could be done by look at the eigenvalues of the Hamiltonian, if the eigenvalues are all positive then the Hamiltonian is positive definite. As to why it matters, sometimes having systems with negative energy isn't really physically meaningful. | |
| Jun 2 at 14:44 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited tags
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| S Jun 2 at 13:38 | history | edited | Vincent Thacker | CC BY-SA 4.0 |
improving title
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| S Jun 2 at 13:38 | history | suggested | Sancol. | CC BY-SA 4.0 |
improving title
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| Jun 2 at 13:12 | review | Suggested edits | |||
| S Jun 2 at 13:38 | |||||
| Jun 2 at 12:56 | history | asked | codebpr | CC BY-SA 4.0 |