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Qmechanic
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I was going through this paper on QCD chaos, where in Appendix B (page 10), for equation B12: $$\frac{\mathcal{S}}{\mathcal{T}}= \int \mathrm{d}t\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1.$$$$\frac{\mathcal{S}}{\mathcal{T}}= \int \mathrm{d}t\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1.\tag{B12}$$

The authors state that:

The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed.

My question is how to verify that kinetic term is not positive definite for some regions and why is it important?

I was going through this paper on QCD chaos, where in Appendix B (page 10), for equation B12: $$\frac{\mathcal{S}}{\mathcal{T}}= \int \mathrm{d}t\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1.$$

The authors state that:

The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed.

My question is how to verify that kinetic term is not positive definite for some regions and why is it important?

I was going through this paper on QCD chaos, where in Appendix B (page 10), for equation B12: $$\frac{\mathcal{S}}{\mathcal{T}}= \int \mathrm{d}t\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1.\tag{B12}$$

The authors state that:

The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed.

My question is how to verify that kinetic term is not positive definite for some regions and why is it important?

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Vincent Thacker
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I was going through this paper on QCD chaos, where in Appendix B (page 10), for equation B12:

$$\frac{\mathcal{S}}{\mathcal{T}}= \int dt\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1$$ $$\frac{\mathcal{S}}{\mathcal{T}}= \int \mathrm{d}t\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1.$$

theThe authors state that: "The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed."

The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed.

My question is how to verify that kinetic term is not positive definite for some regions and why is it important?

I was going through this paper on QCD chaos, where in Appendix B (page 10), for equation B12:

$$\frac{\mathcal{S}}{\mathcal{T}}= \int dt\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1$$

the authors state that: "The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed."

My question is how to verify that kinetic term is not positive definite for some regions and why is it important?

I was going through this paper on QCD chaos, where in Appendix B (page 10), for equation B12: $$\frac{\mathcal{S}}{\mathcal{T}}= \int \mathrm{d}t\sum _{n=0,1} \left(\dot{c}_n^2-c_n^2 \omega _n^2\right)+11.3c_0^3+21.5 c_0 c_1^2+10.7c_0 \dot{c}_0^2+3.32 c_0 \dot{c}_1^2+6.64\dot{c}_0 c_1 \dot{c}_1.$$

The authors state that:

The action (B12) describes the motion of the string in a trapping potential with an unstable equilibrium point on its edge, as explained above. One problem of this action is that the kinetic term of the Hamiltonian constructed from this action is not positive definite in some regions within the trapping potential, hence the time evolution there is not well-posed.

My question is how to verify that kinetic term is not positive definite for some regions and why is it important?

Why the kinetic term of the hamiltonianHamiltonian has to be positive definite for well-posed time evolution?

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