An emf is a source of voltage, such as a battery, that converts some other energy form (chemical, mechanical) to electrical energy. Contrast that to a voltage that results from the current generated by an emf, such as the voltage drop across a resistor connected to a battery. In short, an emf is a voltage source.

The formula to find the power that a battery makes available to a circuit, is the same as the formula utilized to find the dissipated power. This means that the power available to the circuit equals the power dissipated.

So, first question:

Why is that so?

Conservation of energy. The chemical potential energy of the battery is dissipated as heat in the circuit resistance, as well as internal resistance of the battery.

About the electromotive force: What's wrong with my thought process? Can someone help me?

For one thing your thought process is (for me at least) difficult to understand, in particular, your distinction between “dissipated” and “useful” power and its relevance to emf versus voltage. Power dissipated in resistance can be useful, as in an electric heater, or not useful, as when dissipated in resistance as a byproduct of the operation of an electric motor (useful power).

The point is emf is a source of voltage and thus power, whether useful or not, and conservation of energy dictates that the power generated by the source of the emf equals the power consumed by devices connected to the source of the emf.

Hope this helps.

An emf is a source of voltage, such as a battery, that converts some other energy form (chemical, mechanical) to electrical energy. Contrast that to a voltage that results from the current generated by an emf, such as the voltage drop across a resistor connected to a battery. In short, an emf is a voltage source.

The formula to find the power that a battery makes available to a circuit, is the same as the formula utilized to find the dissipated power. This means that the power available to the circuit equals the power dissipated.

So, first question:

Why is that so?

Conservation of energy. The chemical potential energy of the battery is dissipated as heat in the circuit resistance, as well as internal resistance of the battery.

About the electromotive force: What's wrong with my thought process? Can someone help me?

For one thing your thought process is (for me at least) difficult to understand, in particular, your distinction between “dissipated” and “useful” power and its relevance to emf versus voltage. Power dissipated in resistance can be useful, as in an electric heater, or not useful, as when dissipated in resistance as a byproduct of the operation of an electric motor (useful power).

The point is emf is a source of voltage and thus power, whether useful or not, and conservation of energy dictates that the power generated by the source of the emf equals the power consumed by devices connected to the source of the emf, regardless of whether that power is considered "useful".

Hope this helps.

An emf is a source of voltage that is generated by converting some other energy form (chemical, mechanical) to electrical energy, such as a battery. Contrast that to a voltage that results from the current generated by an emf, such as the voltage drop across a resistor connected to a battery. In short, an emf is a voltage source.

The formula to find the power that a battery makes available to a circuit, is the same as the formula utilized to find the dissipated power. This means that the power available to the circuit equals the power dissipated.

So, first question:

Why is that so?

Conservation of energy. The chemical potential energy of the battery is dissipated as heat in the circuit resistance, as well as internal resistance of the battery.

About the electromotive force: What's wrong with my thought process? Can someone help me?

For one thing your thought process is (for me at least) difficult to understand, in particular, your distinction between “dissipated” and “useful” power and its relevance to emf versus voltage. Power dissipated in resistance can be useful, as in an electric heater, or not useful, as when dissipated in resistance as a byproduct of the operation of an electric motor (useful power).

The point is emf is a source of voltage and thus power, whether useful or not, and conservation of energy dictates that the power generated by the source of the emf equals the power consumed by devices connected to the source of the emf.

Hope this helps.

An emf is a source of voltage, such as a battery, that converts some other energy form (chemical, mechanical) to electrical energy. Contrast that to a voltage that results from the current generated by an emf, such as the voltage drop across a resistor connected to a battery. In short, an emf is a voltage source.

The formula to find the power that a battery makes available to a circuit, is the same as the formula utilized to find the dissipated power. This means that the power available to the circuit equals the power dissipated.

So, first question:

Why is that so?

Conservation of energy. The chemical potential energy of the battery is dissipated as heat in the circuit resistance, as well as internal resistance of the battery.

About the electromotive force: What's wrong with my thought process? Can someone help me?

For one thing your thought process is (for me at least) difficult to understand, in particular, your distinction between “dissipated” and “useful” power and its relevance to emf versus voltage. Power dissipated in resistance can be useful, as in an electric heater, or not useful, as when dissipated in resistance as a byproduct of the operation of an electric motor (useful power).

The point is emf is a source of voltage and thus power, whether useful or not, and conservation of energy dictates that the power generated by the source of the emf equals the power consumed by devices connected to the source of the emf.

Hope this helps.