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Well,I Don't understand what do you mean by ''Now let us consider all the other objects in the universes except this rocket removed''. Because in newtonian mechanics, it doesn’t matter whether you remove anything from surrounding or not.If they do not become a obstacle for the Rocket,they do not impact the kinetic energy of the rocket.If you go by Einstein relativity then It's also depend on which frame of reference we are considering.So Either your question is uncleared or i simply Don't understand what you are trying to say.But in general you use K.E=1/2 m.v^2E=$1/2 m \cdot v^2$ or K.E=m*c^2 [√{1-(v^2/c^2)}-1]E=$m \cdot c^2 [\sqrt{1-(v^2/c^2)}-1]$ Since you've mention that the rockets velocity is 99.99% of the Light speed,i prefer you to use the second formula.There are many derived form of that equation.I've just given you the simple one.Hope this helps you.And advance sorry if i've made any mistake.

Well,I Don't understand what do you mean by ''Now let us consider all the other objects in the universes except this rocket removed''. Because in newtonian mechanics, it doesn’t matter whether you remove anything from surrounding or not.If they do not become a obstacle for the Rocket,they do not impact the kinetic energy of the rocket.If you go by Einstein relativity then It's also depend on which frame of reference we are considering.So Either your question is uncleared or i simply Don't understand what you are trying to say.But in general you use K.E=1/2 m.v^2 or K.E=m*c^2 [√{1-(v^2/c^2)}-1] Since you've mention that the rockets velocity is 99.99% of the Light speed,i prefer you to use the second formula.There are many derived form of that equation.I've just given you the simple one.Hope this helps you.And advance sorry if i've made any mistake.

Well,I Don't understand what do you mean by ''Now let us consider all the other objects in the universes except this rocket removed''. Because in newtonian mechanics, it doesn’t matter whether you remove anything from surrounding or not.If they do not become a obstacle for the Rocket,they do not impact the kinetic energy of the rocket.If you go by Einstein relativity then It's also depend on which frame of reference we are considering.So Either your question is uncleared or i simply Don't understand what you are trying to say.But in general you use K.E=$1/2 m \cdot v^2$ or K.E=$m \cdot c^2 [\sqrt{1-(v^2/c^2)}-1]$ Since you've mention that the rockets velocity is 99.99% of the Light speed,i prefer you to use the second formula.There are many derived form of that equation.I've just given you the simple one.Hope this helps you.And advance sorry if i've made any mistake.

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created May 1 at 9:08

Albert Newton

Well,I Don't understand what do you mean by ''Now let us consider all the other objects in the universes except this rocket removed''. Because in newtonian mechanics, it doesn’t matter whether you remove anything from surrounding or not.If they do not become a obstacle for the Rocket,they do not impact the kinetic energy of the rocket.If you go by Einstein relativity then It's also depend on which frame of reference we are considering.So Either your question is uncleared or i simply Don't understand what you are trying to say.But in general you use K.E=1/2 m.v^2 or K.E=m*c^2 [√{1-(v^2/c^2)}-1] Since you've mention that the rockets velocity is 99.99% of the Light speed,i prefer you to use the second formula.There are many derived form of that equation.I've just given you the simple one.Hope this helps you.And advance sorry if i've made any mistake.