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S Apr 15 at 12:02 history bounty ended CommunityBot
S Apr 15 at 12:02 history notice removed CommunityBot
Apr 9 at 8:00 comment added Bastam Tajik My personal thumbnail calculation tells me the covering dimension turns out equal to two in the right neighbourhood. Dimensional reduction. @MitchellPorter
Apr 8 at 8:32 comment added Bastam Tajik But I can reassure you that the topology is not locally Euclidean and not Hausdorff. @MitchellPorter
Apr 8 at 6:25 comment added Bastam Tajik No! @MitchellPorter
Apr 7 at 22:42 comment added Mitchell Porter "In case is it a fractal" Do you have any examples of an interval topology that is a fractal?
S Apr 7 at 10:42 history bounty started Bastam Tajik
S Apr 7 at 10:42 history notice added Bastam Tajik Draw attention
Apr 6 at 12:18 history edited Bastam Tajik CC BY-SA 4.0
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Apr 2 at 22:40 comment added Bastam Tajik @LTurner The Lorentzian metric induced topology(Alexandrov's topology(misnomer), or better called interval topology) is strictly coarser than the manifold topology, if and only if the spacetime is not strongly causal.
Apr 2 at 20:50 comment added Miss Understands 1) What's the difference between the induced interval topology and the original manifold topology? 2) How do their basis vectors differ? 3) Is that a stupid question to ask as a question? I asked it before, but nobody answered and I lost a lot of downvote points.
Apr 2 at 20:16 history edited Bastam Tajik CC BY-SA 4.0
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Apr 2 at 15:58 comment added Bastam Tajik Maybe you can ask this totally negligible sort of question prior to ruining the reputation of a question, where decreases the chance of question to be seen by the relevant expert! Nonetheless the answer is: You can answer anyone you feel can answer! @hft
Apr 2 at 15:49 comment added hft "What is the Lebesgue covering dimension of the interval topology induced by the Lorentzian metric g? Does this dimension change in the vicinity of the z axis? In case is it a fractal, what are the necessary and sufficient conditions for it to be so? Is it finite? What is the upper bound on its dimension? ...PS: ...It is possible to prove that..." You should pick one question and ask it clearly.
Apr 2 at 14:43 history edited Bastam Tajik CC BY-SA 4.0
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Apr 2 at 14:10 comment added Bastam Tajik @A.V.S thanks. I corrected it.
Apr 2 at 14:10 history edited Bastam Tajik CC BY-SA 4.0
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Apr 2 at 12:23 comment added Bastam Tajik @A.V.S. physics.stackexchange.com/a/808075/181792
Apr 2 at 12:09 history edited Bastam Tajik CC BY-SA 4.0
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Apr 2 at 10:33 history edited Bastam Tajik CC BY-SA 4.0
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Apr 2 at 0:59 history edited Qmechanic CC BY-SA 4.0
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Apr 1 at 21:32 comment added Bastam Tajik Cross post with: mathoverflow.net/q/467951/503363
Apr 1 at 21:31 history asked Bastam Tajik CC BY-SA 4.0