Timeline for Atomic Sub-shell question
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 31 at 10:51 | comment | added | Samvid Sharma | Thank you so much! | |
| Mar 31 at 10:51 | comment | added | Gabriel Ybarra Marcaida | Usually we take $p_z$ as the one corresponding to $m_l=0$. I'm general, for an energy number $n$, the orbital $l_{z^{n-1}}$, where a is the letter of the corresponding orbital. (See spherical harmonics for more on this). I'll write something better once I get hold of a computer. | |
| S Mar 31 at 10:49 | review | First answers | |||
| Mar 31 at 12:20 | |||||
| S Mar 31 at 10:49 | history | suggested | Gabriel Ybarra Marcaida | CC BY-SA 4.0 |
Corrected typos
|
| Mar 31 at 10:46 | comment | added | Lakshya Dubey | There is no fixed definition of which one is taken as zero. Its your choice. But generally they are assigned to zero for pz. | |
| Mar 31 at 10:42 | review | Suggested edits | |||
| S Mar 31 at 10:49 | |||||
| Mar 31 at 10:38 | comment | added | Samvid Sharma | I know this, but i want to know specifically which orbital in each sub-shell will have $m_l$ equal to 0. Like in p sub-shell, which orbital from $p_x, p_y, p_z$ will have $m_l$ as Zero? | |
| S Mar 31 at 10:28 | review | First answers | |||
| Mar 31 at 10:42 | |||||
| S Mar 31 at 10:28 | history | answered | Lakshya Dubey | CC BY-SA 4.0 |