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Mar 29 at 6:56 comment added Valter Moretti The momentum along the spatial direction $i$ is the spatial integral of $T^{0i}(x)$. Performing computations, a factor $\omega_k$ takes place removing the denominator you found…Your general formula for $\hat{O}$ is only valid for the non relativistic case.
Mar 28 at 10:25 history edited Qmechanic CC BY-SA 4.0
edited tags
Mar 28 at 10:22 history edited SweetTomato CC BY-SA 4.0
Fixed some typos
Mar 28 at 3:44 answer added flippiefanus timeline score: 0
S Mar 27 at 21:58 review First questions
Mar 28 at 6:20
S Mar 27 at 21:58 history asked SweetTomato CC BY-SA 4.0