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Qmechanic
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The short answer is that at this point in Ref. 1 $u^m$ are new independent variables; not functions of $q$ and $p$. Equivalently, $u^m$ are Lagrange undetermined multipliers.

It is possibly helpful to mention that a field redefinition $u^m\to u^m +U^m(q,p)$ is allowed.

References:

  1. M. Henneaux & C. Teitelboim, Quantization of Gauge Systems, 1994; subsection 1.1.4: eqs. (1.12) + (1.13).

  2. P.A.M. Dirac, Lectures on QM, 1964; eqs. (1-7)+ (1-8).

The short answer is that at this point in Ref. 1 $u^m$ are new independent variables; not functions of $q$ and $p$. Equivalently, $u^m$ are Lagrange undetermined multipliers.

References:

  1. M. Henneaux & C. Teitelboim, Quantization of Gauge Systems, 1994; subsection 1.1.4: eqs. (1.12) + (1.13).

  2. P.A.M. Dirac, Lectures on QM, 1964; eqs. (1-7)+ (1-8).

The short answer is that at this point in Ref. 1 $u^m$ are new independent variables; not functions of $q$ and $p$. Equivalently, $u^m$ are Lagrange undetermined multipliers.

It is possibly helpful to mention that a field redefinition $u^m\to u^m +U^m(q,p)$ is allowed.

References:

  1. M. Henneaux & C. Teitelboim, Quantization of Gauge Systems, 1994; subsection 1.1.4: eqs. (1.12) + (1.13).

  2. P.A.M. Dirac, Lectures on QM, 1964; eqs. (1-7)+ (1-8).

Source Link
Qmechanic
  • 213k
  • 48
  • 590
  • 2.3k

The short answer is that at this point in Ref. 1 $u^m$ are new independent variables; not functions of $q$ and $p$. Equivalently, $u^m$ are Lagrange undetermined multipliers.

References:

  1. M. Henneaux & C. Teitelboim, Quantization of Gauge Systems, 1994; subsection 1.1.4: eqs. (1.12) + (1.13).

  2. P.A.M. Dirac, Lectures on QM, 1964; eqs. (1-7)+ (1-8).