Timeline for Why Does Planck's Relation $E=hf$ Imply a Linear Relationship Only for Sinusoidal Frequency Bases?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Mar 9 at 23:37 | comment | added | Agnius Vasiliauskas | Here's take a look. | |
| Mar 9 at 23:30 | comment | added | Agnius Vasiliauskas | No, you misunderstood something. (1) and (2) expressions ARE periodic, which represents square and triangular wave approximations. Try to draw their charts to see that they are periodic. What I mean is that non-sinusoidal waves can be approximated by putting sinusoidal function in some $g(f)$ transformation(s) like I gave you in (1),(2). And so linear relationship $E=h\nu$ still holds for the non-sinusoidal waves, because they are same sinusoidal waves "under the hood". In general all signals can be decomposed into sinusoidal ones by Fourier transform. | |
| Mar 9 at 23:13 | history | edited | Agnius Vasiliauskas | CC BY-SA 4.0 |
added 910 characters in body
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| Mar 9 at 22:39 | comment | added | CuriousMind | Yes but those are not periodic functions as you say. I am talking about why in E=h*f the frequency is of sinusoidal signals, instead of square periodic or triangular signals. Like any of these (look how they repeat constantly with a specific frequency). upload.wikimedia.org/wikipedia/commons/7/77/Waveforms.svg | |
| Mar 9 at 22:37 | history | answered | Agnius Vasiliauskas | CC BY-SA 4.0 |
