Since you have that $$P=I^2R,$$ it is reasonable to think that because an increase in resistance leads to a drop in current that it might be possible this could happen in a way that doesn't always lead to power loss, the change could be such that there is break even, or even less power loss in higher resistance lines, however, the reality of this is not so in practical applications. One hint that this is so is due to the fact that the current is quadratic in the power relation, so a drop in current will still lead to large losses when increasing the resistance. However, in real life practical applications, the current on the transmission lines is largely determined by the consumer power demand and not that of the line resistance, so you get in general, an increases in ohmic losses for an increase in transmission line length. A fact that power plant engineers mitigate for by using AC power transmitting at high voltages.

Since you have that $$P=I^2R,$$ it is reasonable to think that because an increase in resistance leads to a drop in current that it might be possible this could happen in a way that doesn't always lead to power loss, the change could be such that there is break even, or even less power loss in higher resistance lines, however, the reality of this is not so in practical applications. In real life practical applications, the current on the transmission lines is largely determined by the consumer power demand and not that of the line resistance, so you get in general, an increases in ohmic losses for an increase in transmission line length. A fact that power plant engineers mitigate for by using AC power transmitting at high voltages.