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Feb 21 at 21:12 vote accept DrD
Feb 21 at 21:12 comment added DrD OK, got it :) Thanks a lot
Feb 21 at 20:45 comment added octonion There is a metric in the first line of your question. The issue is whether the d'Alembert operator (in Cartesian coordinates in flat space) reduces to $\partial_t^2 - \partial_x^2$ or $-\partial_t^2 + \partial_x^2$. When you see someone using $-m^2$ they have the second definition in mind.
Feb 21 at 20:39 comment added DrD Thanks for your answer, octonion. I had already considered that option, but I haven't had to specify any metric in my derivation. So I am not convinced yet.
Feb 21 at 20:27 history answered octonion CC BY-SA 4.0