Timeline for The time-dependence of the expectation values of spin operators
Current License: CC BY-SA 4.0
4 events
when toggle format | what | by | license | comment | |
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Feb 22 at 10:36 | vote | accept | ilra | ||
Feb 21 at 19:18 | comment | added | Matteo | I have actually computed $\exp{(-iHt/\hbar)} = \exp{(-i \frac{wt}{2} S_z)}$, then I have exponentiated the diagonal matrix $\mathrm{diag}{(-iwt/2, +iwt/2})$, which is a diagonal matrix having the exponential of the eigenvalues as diagonal elements | |
Feb 21 at 19:14 | comment | added | ilra | Ahh that was very helpful! Appreciate the help:) but I have one question about the matrix exponential, you replaced the H in the exponent with w instead of wS_z, should not S_z also be in the matrix representation of the time operator? | |
Feb 21 at 18:18 | history | answered | Matteo | CC BY-SA 4.0 |