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John Rennie
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This problem has 2 questions. The

The 1st is : if ρ=Ar , the relation between E and p. The

The 2ed is : if I want p=αE , how to solve ρ? Lets

Lets solve 2ed question: Assume

Assume ρ=B (B is a constant). ∮E⋅da=E(4πr²)=Q

∮E⋅da=E(4πr²)=Q/(ε₀)=∫B4πr²dr/(ε₀) . We

We can solve: E=Br

E=Br/3(ε₀), so

so r=3(ε₀)E/B, so

so p=qr=3q(ε₀)E/B, then

then we can see p is proportional to E. So

So we can see if ρ=B(the charge density is a constant),p is proportional to E.

This problem has 2 questions. The 1st is : if ρ=Ar , the relation between E and p. The 2ed is : if I want p=αE , how to solve ρ? Lets solve 2ed question: Assume ρ=B (B is a constant). ∮E⋅da=E(4πr²)=Q/(ε₀)=∫B4πr²dr/(ε₀) . We can solve: E=Br/3(ε₀), so r=3(ε₀)E/B, so p=qr=3q(ε₀)E/B, then we can see p is proportional to E. So we can see if ρ=B(the charge density is a constant),p is proportional to E.

This problem has 2 questions.

The 1st is : if ρ=Ar , the relation between E and p.

The 2ed is : if I want p=αE , how to solve ρ?

Lets solve 2ed question:

Assume ρ=B (B is a constant).

∮E⋅da=E(4πr²)=Q/(ε₀)=∫B4πr²dr/(ε₀) .

We can solve:

E=Br/3(ε₀),

so r=3(ε₀)E/B,

so p=qr=3q(ε₀)E/B,

then we can see p is proportional to E.

So we can see if ρ=B(the charge density is a constant),p is proportional to E.

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This problem has 2 questions. The 1st is : if ρ=Ar , the relation between E and p. The 2ed is : if I want p=αE , how to solve ρ? Lets solve 2ed question: Assume ρ=B (B is a constant). ∮E⋅da=E(4πr²)=Q/(ε₀)=∫B4πr²dr/(ε₀) . We can solve: E=Br/3(ε₀), so r=3(ε₀)E/B, so p=qr=3q(ε₀)E/B, then we can see p is proportional to E. So we can see if ρ=B(the charge density is a constant),p is proportional to E.