Timeline for How is the interference pattern of the double slit experiment quantitatively measured? [closed]
Current License: CC BY-SA 4.0
26 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 16 at 5:42 | history | left closed in review |
Hyperon Jon Custer Miyase |
Original close reason(s) were not resolved | |
| Feb 15 at 19:05 | history | edited | Blacklight MG | CC BY-SA 4.0 |
added 29 characters in body
|
| S Feb 15 at 18:44 | review | Reopen votes | |||
| Feb 16 at 5:42 | |||||
| S Feb 15 at 18:44 | history | edited | Blacklight MG | CC BY-SA 4.0 |
correction
Added to review
|
| Feb 15 at 18:33 | comment | added | Blacklight MG | @DavidBailey I'm referring to the radius of the photon as observed in the interference pattern, when the wavefunction collapses. If it was a point particle, we wouldn't see anything, but we do. So what exactly is happening there? | |
| Feb 15 at 18:27 | comment | added | David Bailey | If you want to know how the "the radius of the photon" could be experimentally measured from an interference pattern, you could ask about that, but first look you'd need to define what you mean by "radius of a photon". I suggest looking at "Can a photon have a radius?" and "What is Size of Photon?". | |
| Feb 15 at 17:24 | comment | added | Blacklight MG | @DavidBailey I mean I wish to know the radius of the photon. I though the electric field would be the right value to measure. By generic I meant any, such as UV or IR, not all. | |
| Feb 15 at 16:56 | comment | added | David Bailey | No single type of instrument can detect "generic electromagnetic waves", but only some specific region of the electromagnetic spectrum. Specifying that you want to measure the electric field actually confuses the issue. You can make "screens" of CCD or photographic film, but these are quantum devices that count photons (or electrons) with high enough energy; they do not directly measure the electric field. On the other hand, microwave detectors do measure the electric field, but microwave interference is usually measured by scanning a detector across the pattern; no screen is involved. | |
| Feb 15 at 5:43 | comment | added | Blacklight MG | @DavidBailey I was talking about generic electromagnetic wave interference, but the same applies for electrons as well. But not water. Intensity should be the electric field obtained at the screen due to the light falling on it. I want to measure it to see how concentrated the the intensities are at different oarts of the screen, aside from visual observations, which may be due to optical illusions too. | |
| Feb 14 at 15:17 | comment | added | David Bailey | Interference of what: electrons, light, x-rays, microwaves, water waves, …? You mention a "screen", so it is unlikely to be water, but electrons, light, and x-rays could also by imaged by a screen. (And that does not include interference observed on an oscilloscope screen.) What is the wavelength? What is the size scale of the interference pattern? What is the intensity? Why do you want to quantitatively measure the pattern? I did not notice this question when it was posted or vote to close it, but I understand why it was closed. | |
| Feb 14 at 14:48 | history | left closed in review |
Jon Custer Hyperon David Bailey |
Original close reason(s) were not resolved | |
| Feb 14 at 9:19 | history | edited | Qmechanic♦ |
edited tags; edited tags; edited tags
|
|
| S Feb 14 at 8:51 | review | Reopen votes | |||
| Feb 14 at 14:48 | |||||
| S Feb 14 at 8:51 | history | edited | Blacklight MG | CC BY-SA 4.0 |
Edited the question for reopening, and I also have an answer to it now (Using Single Photon Avalanche Detectors)
Added to review
|
| Feb 7 at 13:52 | history | left closed in review |
Hyperon Miyase jng224 |
Original close reason(s) were not resolved | |
| S Feb 7 at 9:19 | review | Reopen votes | |||
| Feb 7 at 13:52 | |||||
| S Feb 7 at 9:19 | history | edited | Blacklight MG | CC BY-SA 4.0 |
The question was pretty simple and I got an answer.. perhaps I should've mentioned the field obtained on the screen instead of something that's already on it.
Added to review
|
| Feb 7 at 9:16 | comment | added | Blacklight MG | @JonCuster CCD was exactly what I was asking about. They are measuring the charge density created by the fields.. so I wanted to know that. | |
| Feb 7 at 9:14 | vote | accept | Blacklight MG | ||
| Feb 6 at 18:50 | history | closed |
Hyperon Jon Custer Miyase |
Needs details or clarity | |
| Feb 6 at 13:43 | comment | added | Farcher | The ear for sound! | |
| Feb 6 at 13:36 | answer | added | John Doty | timeline score: 1 | |
| Feb 6 at 13:34 | comment | added | John Doty | Why the close votes? This is a perfectly clear question. | |
| Feb 6 at 13:16 | review | Close votes | |||
| Feb 6 at 18:50 | |||||
| Feb 6 at 13:06 | comment | added | Jon Custer | CCD imagers are pretty quantitative. And why should the screen have an electric field? | |
| Feb 6 at 12:51 | history | asked | Blacklight MG | CC BY-SA 4.0 |