Timeline for Time taken for a rocket to travel upwards
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 4 at 14:42 | vote | accept | Star Gazer | ||
| Feb 4 at 13:40 | comment | added | Truth and Beauty and Hatred | Well in this case I am evaluating a finite potential energy difference $\Delta U=U(h)-U(h_0=0)$, there is no infinitesimal variation. Note also that if you want to evaluate a infinitesimal energy variation the correct formula would be \begin{equation} dU= \frac{dU}{dh} dh= -F_{grav} dh \end{equation}where i used the fact that $F_{grav}=- \frac{dU}{dh}$ | |
| Feb 4 at 11:55 | comment | added | Star Gazer | Thanks a lot for the answer and yes i actually meant constant force srry for confusion. I did understand the method of conservation of energy, the way how you did it, but i still am stuck and unable to understand, how there ,at the demoninators(R+h of both the equations), have you put R+h . Shouldnt it be R+dh since the potential energy or the gravitational attraction is minutely increasing with infinitely small values of h. | |
| S Feb 4 at 9:46 | review | First answers | |||
| Feb 4 at 11:06 | |||||
| S Feb 4 at 9:46 | history | answered | Truth and Beauty and Hatred | CC BY-SA 4.0 |