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Jan 13 at 15:33 vote accept Photon
Jan 13 at 15:33 vote accept Photon
Jan 13 at 15:33
Jan 7 at 8:45 comment added Photon Thank you very much! Now I know how to get $a(t)$. But I'm still confused about why there isn't $t^{\frac{2}{3}(1+w)}\sim e^{Ht}$ when $w\to -1$. Could you please explain more about what's the physics in it?
Jan 4 at 14:30 history answered Navid CC BY-SA 4.0