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Oct 10, 2014 at 17:57 comment added HolgerFiedler Perhaps this helps: physics.stackexchange.com/questions/114859
Sep 29, 2013 at 19:19 comment added user4552 @Nathaniel: Fair enough. I guess it depends on the extent to which you buy operationalism as a philosophical position: plato.stanford.edu/entries/operationalism . I tend toward operationalism, although it does have its limitations, e.g., it says you can't really talk about an electron's wavefunction, which we clearly want to do.
Sep 29, 2013 at 10:37 comment added N. Virgo @BenCrowell sure, we can measure those things, but that doesn't necessarily tell us how to interpret their meaning. The question of "what's oscillating" for a single photon seems a very reasonable and well-defined one to me.
Sep 29, 2013 at 6:17 history tweeted twitter.com/#!/StackPhysics/status/384200132205752320
Sep 29, 2013 at 2:44 answer added Selene Routley timeline score: 21
Sep 29, 2013 at 2:25 answer added user26165 timeline score: 0
Sep 29, 2013 at 0:53 answer added anna v timeline score: 6
Sep 29, 2013 at 0:40 comment added user4552 Do you mean that ... No, I'm just saying that your question is vague and I can't tell what you're asking. In that case, what would be the amplitude... This seems like a separate question, but anyway you could estimate the amplitude if you knew the volume occupied by the wavetrain. Equate the energy of the photon to the energy of a classical EM wave occupying that volume, and solve for the amplitude.
Sep 29, 2013 at 0:37 comment added Phyllipe In that case, what would be the amplitude of that oscillation? I mean, what physical variable would be associated with that amplitude?
Sep 29, 2013 at 0:14 comment added Phyllipe Do you mean that a single photon is linearly polarized when it oscillates forming a straight line and the frequency of this oscillation is that of the electromagnetic wave?
Sep 29, 2013 at 0:09 review First posts
Sep 29, 2013 at 0:16
Sep 29, 2013 at 0:08 comment added user4552 This is pretty vague. Why do you think they're difficult to interpret? We have devices that can detect individual photons, and filters that can filter photons based on polarization and frequency, so it seems clear to me that these concepts are well founded for a single photon. What we don't have in the case of a single photon is a sharply defined phase or classically measurable E and B fields.
Sep 28, 2013 at 23:58 history edited Phyllipe CC BY-SA 3.0
Translation fixed
Sep 28, 2013 at 23:52 history asked Phyllipe CC BY-SA 3.0