Timeline for It seems that expectation value of $H$ on coherent states is independent of time? But why?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 3, 2023 at 22:49 | vote | accept | Damark | ||
| Nov 3, 2023 at 17:02 | comment | added | Hyperon | @Damark Never ever cancel a question! Someone else might find the question/answer useful. | |
| Nov 3, 2023 at 16:59 | comment | added | Damark | Oh, I'm very stupid. Sorry, and thank you Marh and Hyperon. (Should I cancel the question?) | |
| Nov 3, 2023 at 16:49 | comment | added | march | @Damark The expectation value of the Hamiltonian is always time-independent in any state, because it represents the total energy and is hence conserved. This is the physical content of this answer. (If the Hamiltonian is time-dependent, this isn't true, though.) | |
| Nov 3, 2023 at 16:45 | comment | added | Damark | Mathematically it's okay. But what is the physical meaning of this? if $|\psi \rangle$ is an eigenket of $H$ I see clear the physical meaning (is an eigenstate, of course, when you measure the state of particle you obtain those eigenstate). But coherent state is not an eigenstates of $H$. It is a superposition. And it evolve over time. Why it's expectation value of energy is not time dependent? | |
| Nov 3, 2023 at 16:38 | history | answered | Hyperon | CC BY-SA 4.0 |