Timeline for Application of Newton's laws
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Mar 18 at 16:50 | vote | accept | Atticus Waters | ||
| Oct 29, 2023 at 13:30 | history | edited | Bob D | CC BY-SA 4.0 |
deleted 21 characters in body
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| Oct 28, 2023 at 16:11 | comment | added | Bob D | @Not_Einstein No problem. I edited my answer to simply refer to the tension force T acting on both masses | |
| Oct 28, 2023 at 15:04 | comment | added | Not_Einstein | Maybe I could have worded it better i.e. that F12 and F21 are the magnitudes of the forces (hence positive numbers). | |
| Oct 28, 2023 at 12:50 | history | edited | Bob D | CC BY-SA 4.0 |
simplification
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| Oct 28, 2023 at 9:02 | history | edited | Bob D | CC BY-SA 4.0 |
clarification
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| Oct 28, 2023 at 0:08 | comment | added | Bob D | @Not_Einstein "let's assume F12 and F21 are positive numbers." I don't understand what you mean by this statement. F12 and F21 are force vectors having the same magnitude but opposite direction. Please elaborate | |
| Oct 27, 2023 at 20:09 | comment | added | Not_Einstein | In your diagram let's assume F12 and F21 are positive numbers. F12 is the force the string exerts on m2, so by Newton's 3rd law -F12 (to the left) is the force m2 exerts on the string. In you diagram, F21 is the force the string exerts on m1, so by Newton's 3rd law F21 (to the right) is the force m1 exerts on the string. Adding the forces on the string, F21-F12 = ma where m is the mass of the string. Assuming a massless string, F12 = F21. It appears you skipped some of these steps by not applying Newton's 3rd law correctly. | |
| Oct 27, 2023 at 16:09 | history | edited | Bob D | CC BY-SA 4.0 |
Clarification
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| Oct 27, 2023 at 13:05 | comment | added | Bob D | @Not_Einstein Not sure what you are trying to say. In the diagram, the force that m2 exerts on the string is F21 and the force m1 exerts on the string is F12. The two forces are equal and opposite per N3. | |
| Oct 27, 2023 at 12:34 | comment | added | Not_Einstein | "Then since the force the connecting string applies to 𝑚2 has to be equal and opposite to the force the connecting string exerts on 𝑚1 per Newton's 3rd law..." Per Newton's 3rd law it has to be equal to the force m2 exerts on the string, no? | |
| Oct 27, 2023 at 12:25 | history | edited | Bob D | CC BY-SA 4.0 |
edited body
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| Oct 27, 2023 at 12:19 | history | edited | Bob D | CC BY-SA 4.0 |
additional information
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| Oct 26, 2023 at 20:47 | history | answered | Bob D | CC BY-SA 4.0 |